VBGamer

I don't think so Mattman... :P The first VarPtr call (the one nested within the other one) would create a temporary variable in memory in which the address of the byte would be stored. The second VarPtr call would return the address of this temp variable. The temp variable would disappear, and the second address would no longer be valid, or point to some other random data. If I'm wrong I'm sorry, but that's how I see it working. David